SolarSizer

What Size Solar System Do I Need for 1,000 kWh per Month?

A 1,000 kWh bill is a little above the U.S. monthly average. The Phoenix year and the 4-hour generic estimate do not land on the same kilowatts.

Full breakdown: what size solar system.

Panel-count context for a whole house: how many solar panels.

Quick answer: For a 1,000 kWh month, the Phoenix PVWatts path is 6.84 kW: 12,000 kWh/year ÷ 1,755 kWh per kW per year. The generic path, using 4 and 5 peak sun hours and PVWatts' 14% default losses, is 9.69 kW and 7.75 kW. Plan from your own bills in PVWatts or the solar size calculator.
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Kilowatts, two ways

MethodArray400 W panels, rounded upSource
Phoenix year: annual kWh ÷ 1,7556.84 kW18PVWatts v8
4 peak sun hours, then ÷ (1 − 0.14)9.69 kW25Battle Born hours; PVWatts v5 losses
5 peak sun hours, then ÷ (1 − 0.14)7.75 kW20Battle Born hours; PVWatts v5 losses

The 1,000 kWh rows use the same Phoenix run: 1,755 kWh per kW, lat 33.45, lon −112.07, fixed open rack, tilt 20°, azimuth 180°. 400 W is only the divisor for the panel column.

How to size it

A 1,000 kWh month is the worked example people expect from a bill, so the loss categories behind the 14% term are spelled out here and not repeated as a list on the other monthly pages. Start with the year, then the day.

  1. Annual energy: 1,000 × 12 = 12,000 kWh.
  2. Phoenix array: 12,000 ÷ 1,755 = 6.84 kW. That 1,755 is AC kilowatt-hours per kilowatt of DC for the Phoenix inputs in the PVWatts v8 run. Unrounded, an illustrative 400 W panel count rounds up to 18.
  3. Daily energy: 1,000 ÷ 30 = 33.33 kWh. The 30-day step compares the bill with a monthly average; EIA does not print the number 30.
  4. 4 peak sun hours: (33.33 ÷ 4) ÷ (1 − 0.14) = 9.69 kW, which rounds up to 25 illustrative 400 W panels.
  5. 5 peak sun hours: (33.33 ÷ 5) ÷ (1 − 0.14) = 7.75 kW, which rounds up to 20 panels.

EIA's average month is about 899 kWh. 1,000 ÷ 899 = 1.11, so this bill is about 1.11 times that average. The matching annual average is 10,791 kWh; 12,000 ÷ 10,791 = 1.11 as well. On the Phoenix yield those years are 12,000 ÷ 1,755 = 6.84 kW here, and 10,791 ÷ 1,755 = 6.15 kW (about 6.1 kW) on the average-home page.

The 14% in the generic column is PVWatts' default total system losses. The version 5 manual lists the default categories as soiling 2%, shading 3%, mismatch 2%, wiring 2%, connections 0.5%, light-induced degradation 1.5%, nameplate rating 1%, and availability 3%. The manual's point is that the 14% total is not a simple sum of those lines. This page uses the 14% total only, as (1 − 0.14).

The gap from 6.84 kW to 9.69 kW is the weather assumption, not a second bill. Phoenix's year yields 1,755 kWh per kW; the generic column forces the day through 4 peak sun hours and 14% losses. December in that Phoenix run is 4.75 against an annual 6.54. Your roof goes in PVWatts; your appliance list goes in the solar size calculator.

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FAQ

How many kilowatts offset 1,000 kWh a month in Phoenix?

12,000 kWh a year ÷ 1,755 kWh per kW = 6.84 kW. On an illustrative 400 W panel that rounds up to 18.

What do 4 and 5 peak sun hours give?

1,000 ÷ 30 = 33.33 kWh/day. (33.33 ÷ 4) ÷ (1 − 0.14) = 9.69 kW. At 5 peak sun hours the same steps give 7.75 kW.

What is inside the 14% loss?

PVWatts version 5's default total system losses are 14%. The manual lists soiling 2%, shading 3%, mismatch 2%, wiring 2%, connections 0.5%, light-induced degradation 1.5%, nameplate rating 1%, and availability 3%, and it says that 14% is not a simple sum of those categories.

Does this replace a PVWatts run at my house?

No. The 1,755 kWh per kW figure is one Phoenix array at 14% losses. 4 to 5 peak sun hours is a baseline, not this roof's December. Run 12,000 kWh at the real address.

Related questions

All of these questions are listed on the topic map.

Sources